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How to calculate the first N (random up to 100) prime numbers in C#

1 Answer

0 votes
sing System;

namespace ConsoleApplication_C_Sharp
{
    class Program
    {
        static void Main(string[] args)
        {
            Random rnd = new Random();

            int n = rnd.Next(1, 100);

            if (n >= 1)
            {
                Console.WriteLine("First {0} prime numbers are:", n);
                Console.WriteLine("2");
            }

            int prime = 3;
            for (int numbers = 2; numbers <= n;)
            {
                int i;
                for (i = 2; i <= prime - 1; i++)
                {
                    if (prime % i == 0)
                        break;
                }
                if (i == prime)
                {
                    Console.WriteLine("{0}", prime);
                    numbers++;
                }
                prime++;
            }
        }
    }
}


/*
run:
    
First 67 prime numbers are:
2
3
5
7
11
13
17
19
23
29
31
37
41
43
47
53
59
61
67
71
73
79
83
89
97
101
103
107
109
113
127
131
137
139
149
151
157
163
167
173
179
181
191
193
197
199
211
223
227
229
233
239
241
251
257
263
269
271
277
281
283
293
307
311
313
317
331
   
*/

 





answered May 9, 2016 by avibootz
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