Question

How to find the largest three elements in an array with TypeScript

Answer 1

function print3largest(arr: number[]) {
	const size = arr.length;
   
 	if (size < 3) {
        console.log("array size < 3");
        return;
    }
 
 	let first, second, third;
 	
    third = first = second = Number.MIN_VALUE;
    
    for(let i = 0; i < size; i++) {
        if (arr[i] > first) {
            third = second;
            second = first;
            first = arr[i];
        }
        else if (arr[i] > second) {
            third = second;
            second = arr[i];
        }
        else if (arr[i] > third)
            third = arr[i];
    }
 
    console.log("The three largest elements are: " + first + " " + second + " "  + third);
}
 

const arr = [5, 2, 9, 6, 12, 7, 8, 3, 1, 0];
     
print3largest(arr);



/*
run:
      
"The three largest elements are: 12 9 8" 
      
*/
    

 

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