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How to sum elements of deque values in C++

2 Answers

0 votes
#include <iostream> 
#include <deque> 
 
int sumdq(std::deque <int> dq) { 
    int sum = 0;
    while (!dq.empty()) { 
        sum += dq.front(); 
        dq.pop_front(); 
    } 
    return sum;
} 
   
int main() 
{ 
    std::deque<int> dq;
     
    dq.push_back(4); 
    dq.push_back(2); 
    dq.push_back(5); 
    dq.push_back(1); 
    dq.push_back(9); 
    dq.push_back(8);  
  
    std::cout << sumdq(dq);
 
     
    return 0; 
} 
 
 
 
/*
run:
 
29
 
*/

 




answered Jul 21 by avibootz
0 votes
#include <iostream> 
#include <deque> 
   
void printdq(std::deque <int> dq) { 
    for (auto &n: dq)
        std::cout << n << ", ";
    std::cout << '\n'; 
} 

int sumdq(std::deque <int> dq) { 
    int sum = 0;
    for (auto &n: dq)
        sum += n;
    return sum;
} 
   
int main() 
{ 
    std::deque<int> dq = { 1, 2, 3, 4, 5, 6 }; 
       
    printdq(dq); 

    std::cout << '\n' << sumdq(dq); 
    
    return 0; 
} 
     
     
     
/*
run:
     
1, 2, 3, 4, 5, 6, 

21
 
*/

 




answered 6 days ago by avibootz
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