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How to find the length of longest common subsequence (LCS) present in two strings with C++

2 Answers

0 votes
// A c++ program that find the length of longest common subsequence (LCS) present in two strings 
 
#include <bits/stdc++.h> 
#include <iostream>

using namespace std;
   
int mymax(int a, int b) { 
    return (a > b) ? a : b; 
} 
   
int lcs(char *s1, char *s2, int lens1, int lens2) { 
    if (lens1 == 0 || lens2 == 0) 
        return 0; 
    if (s1[lens1 - 1] == s2[lens2 - 1]) 
        return 1 + lcs(s1, s2, lens1 - 1, lens2 - 1); 
    else
        return mymax(lcs(s1, s2, lens1, lens2 - 1), lcs(s1, s2, lens1 - 1, lens2)); 
} 
   
int main() 
{ 
    char s1[] = "accyrb";
    char s2[] = "cyxyazb";
 
    cout << "Length of LCS is " << lcs(s1, s2, strlen(s1), strlen(s2)); 
   
    return 0; 
} 
 
 
/*
run:
 
Length of LCS is 3
 
*/

 




answered Jun 7 by avibootz
edited Jun 7 by avibootz
0 votes
// A c++ program that find the length of longest common subsequence (LCS) present in two strings 
 
#include <iostream>
#include <string>

using namespace std;
   
int mymax(int a, int b) { 
    return (a > b) ? a : b; 
} 
   
int lcs(string s1, string s2, int lens1, int lens2) { 
    if (lens1 == 0 || lens2 == 0) 
        return 0; 
    if (s1[lens1 - 1] == s2[lens2 - 1]) 
        return 1 + lcs(s1, s2, lens1 - 1, lens2 - 1); 
    else
        return mymax(lcs(s1, s2, lens1, lens2 - 1), lcs(s1, s2, lens1 - 1, lens2)); 
} 
   
int main() 
{ 
    string s1 = "accyrb";
    string s2 = "cyxyazb";
 
    cout << "Length of LCS is " << lcs(s1, s2, s1.length(), s2.length()); 
   
    return 0; 
} 
 
 
/*
run:
 
Length of LCS is 3
 
*/

 




answered Jun 7 by avibootz
...