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How to extend initialized array with a range of int numbers in Python

2 Answers

0 votes
import array 

a = array.array('i', range(5)) # i = int

print(a)   
print(a[1:4])
print(a[2:3])
print(a[0])
print(a[3])

a.extend(range(4))
print(a) 



'''
run:
 
array('i', [0, 1, 2, 3, 4])
array('i', [1, 2, 3])
array('i', [2])
0
3
array('i', [0, 1, 2, 3, 4, 0, 1, 2, 3])

'''

 




answered May 11 by avibootz
0 votes
import array 
 
a = array.array('i', range(5)) # i = int
 
print(a)   
print(a[1:4])
print(a[2:3])
print(a[0])
print(a[3])
 
a.extend(range(5, 9))
print(a) 
 
 
 
'''
run:
  
array('i', [0, 1, 2, 3, 4])
array('i', [1, 2, 3])
array('i', [2])
0
3
array('i', [0, 1, 2, 3, 4, 5, 6, 7, 8])
 
'''

 




answered May 11 by avibootz
...