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How to swap the first 4 bits of a number with the last 4 bits in Java

1 Answer

0 votes
import java.io.*;  
    
public class MyClass {
    public static void main(String args[]) {
        int n = 92; 

        System.out.println(Integer.toBinaryString(n)); 
  
        n = ((n & 0xf0) >> 4) | ((n & 0x0f) << 4);
   
        System.out.println(Integer.toBinaryString(n)); 
    }
}
    
 
    
/*
run:
    
1011100
11000101
   
*/

 




answered Mar 14 by avibootz
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