Question

How to print the ABC with pointers in C

Answer 1

#include <stdio.h>
 
void print(char *p);
 
int main(int argc, char **argv) 
{
    char *abc = "abcdefghijklmnopqrstuvwxyz";
  
    print(abc);
  
    return 0;
}

void print(char *p)
{
    while (*p)
        printf("%c", *p++);
    
    printf("\n");
}

/*
run:

abcdefghijklmnopqrstuvwxyz

*/

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